lucyyoung000 lucyyoung000
  • 03-11-2020
  • Mathematics
contestada

write the equation of a line that goes through (-3,6) and is perpendicular to the line y=3x+10

Respuesta :

rococo908
rococo908 rococo908
  • 03-11-2020

Answer:

y = -1/3x + 5

Step-by-step explanation:

Perpendicular lines have opposite reciprocal slopes, so the slope of the line will be -1/3

Plug in the slope and given point into y = mx + b to solve for b

y = mx + b

6 = -1/3(-3) + b

6 = 1 + b

5 = b

Plug in the slope and b into y = mx + b

y = -1/3x + 5 is the equation of the line

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