caria1nLisscied caria1nLisscied
  • 03-01-2017
  • Physics
contestada

What average net force is required to stop an 8500 kg truck in 10 s if it’s initially traveling at 20 m/s?

Respuesta :

Аноним Аноним
  • 03-01-2017
We have: F = m × v/t
Here, m = 8500 Kg
v = 20 m/s
t = 10 s

Substitute their values into the expression, 
F = 8500 × 20/10
F = 8500 × 2
F = 17000 N

In short, final answer would be 17000 N

Hope this helps!!

Answer Link

Otras preguntas

14. Joe just purchased an oddly shaped piece of property, depicted in the figure below. 10 yds 13 yds I 12 yds 15 yds 24 yds What is the area, in square yards,
The photograph shows wild salmon. What makes wild salmon a renewable resource?
What is the magnitude of the force on a 0. 0150 kg particle placed at p? slader
which point can be used to create a right triangle
which type of figurative language is included in this passage?
if f(x)=x^2+2x-10 what is f(-2)
Please help me with this:
why should we wear mask to school. give advantages reasons and example of just the advantages and reasons ​
What do you think the purpose of political parties
Identify the vertex, equation of the axis of symmetry, y-intercept, and zeros of the graph of a quadratic function.