jerry9 jerry9
  • 01-11-2015
  • Mathematics
contestada

how solve the equation a(n-3)+8=bn solve for n

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TSO
TSO TSO
  • 01-11-2015
a(n-3) + 8 = bn

an - 3a + 8 = bn

an - 3a + 8 = bn

-3a + 8 = bn - an

-3a + 8 = n(b-a)

[tex]\boxed{n=\frac{-3a + 8}{b-a}}[/tex]

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